Question

(99)²
evaluate this by using the identity (a - b)² =a² - 2ab + b²​

Answer 1

Answer:

$(100 - 1) {}^{2} = 100 {}^{2} + 1 {}^{2} - 2 \times 100 \times 1 = 9801$

Answer 2

Answer:

99^2

99^2 =(100−1)^2

99^2 =(100−1)^2It is the form of (a−b)^2

2 , where a=100,b=1

2 , where a=100,b=1Applying the formula (a−b)^2

2 , where a=100,b=1Applying the formula (a−b)^2 =a ^2+b^2 −2ab

2 , where a=100,b=1Applying the formula (a−b)^2 =a ^2+b^2 −2ab99^2 =(100−1)^2

2 , where a=100,b=1Applying the formula (a−b)^2 =a ^2+b^2 −2ab99^2 =(100−1)^2=100^2 + 1^2-2×100×1=10000+1−200=9801

2 , where a=100,b=1Applying the formula (a−b)^2 =a ^2+b^2 −2ab99^2 =(100−1)^2=100^2 + 1^2-2×100×1=10000+1−200=9801hope it helps

2 , where a=100,b=1Applying the formula (a−b)^2 =a ^2+b^2 −2ab99^2 =(100−1)^2=100^2 + 1^2-2×100×1=10000+1−200=9801hope it helpsplease mark as brainlist

2 , where a=100,b=1Applying the formula (a−b)^2 =a ^2+b^2 −2ab99^2 =(100−1)^2=100^2 + 1^2-2×100×1=10000+1−200=9801hope it helpsplease mark as brainlistfollowme