Math, asked by violentbeast, 11 months ago

(99)^3 using suitable Identity

Answers

Answered by jyotitomar
6

Answer:

Answer:(a-b)³= a³-b³-3ab(a-b)

Answer:(a-b)³= a³-b³-3ab(a-b)(99)³=(100-1)³

Answer:(a-b)³= a³-b³-3ab(a-b)(99)³=(100-1)³(99)³=1000000-1-300(100-1)

Answer:(a-b)³= a³-b³-3ab(a-b)(99)³=(100-1)³(99)³=1000000-1-300(100-1)(99)³=1000000-1-29700

Answer:(a-b)³= a³-b³-3ab(a-b)(99)³=(100-1)³(99)³=1000000-1-300(100-1)(99)³=1000000-1-29700(99)³=970299

Answered by master55538
8

Answer:

(100-1)^3=a^3-b^3-3ab(a-b)

=100^3-1^3-3(100)(1)(100-1)

=1000000-1-300(99)

=999999-29700

=970299 is the answer

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