(99)3using suitable identities
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99 can be written as (100-1)
So, according to the question,
(100-1)^3
The general form is (a-b)^3= a^3 -3a^2b +3ab^2 -b^3
So, (100)^3 -3 (100)^2 (1) +3 (100) (1)^3 +(1)^3
1000000 -30000+300 +1
970000+301
So the answer is 970301.
So, according to the question,
(100-1)^3
The general form is (a-b)^3= a^3 -3a^2b +3ab^2 -b^3
So, (100)^3 -3 (100)^2 (1) +3 (100) (1)^3 +(1)^3
1000000 -30000+300 +1
970000+301
So the answer is 970301.
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