Question

99*99*99 using any identity with name ​

Answer 1

We have,

$\quad 99 \times 99 \times 99 \\ \\ = {99}^{3} \\ \\ = {(100 - 1)}^{3} \\ \\ = {(100)}^{3} + {( - 1)}^{3} + 3(100)( - 1)(100 - 1) \\ \\ = 1000000 - 1 - 300(99) \\ \\ = 999999 - 29700 \\ \\ = 970299$
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Identity used :
$\underline{\boxed{ \sf {(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b)}}$
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Answer 2

Answer:

$x \times x \times x = {x}^{3}$

so,, 99 * 99 *99 = (99)^3 = 970299