99*99*99 using identity
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Answered by
6
Step-by-step explanation:
(100-1)^3
(100)^3-(1)^3-3(100×1)(100-1)
1000000-1-300(100-1)
1000000-1-30000+300
1000000-1-29700
970300-1=970299
I think u Understand the answer.
Answered by
6
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