Math, asked by shashinanagarjuh, 5 months ago

99÷99999 please solve this step by step

Answers

Answered by shivanibansal393

1

Answer:

1010.0909091 is the answer

Answered by shuklaabhinav194

0

Answer:

99÷99999

=33/33333(cutting by 3)

=11/11111(cutting by 3)

Now dividing 11 by 111111

11111|110000|0.0099000

99999

100010

99999

11000

hence,the approx value of quotient =0.0099Ans

Previous Question

Next Question

Similar questions

CBSE BOARD X, 2 months ago

pls answer this question...

Computer Science, 2 months ago

How do you find the remainder of two values in qbasic...

Math, 2 months ago

1) Which of the following is a prime number? a)81 b)87 c)91 d)97 2)Which of the following is a composite number? a)23 b)29 c)32 d)5 3)Which of the following are co-prime? a)8,12 b)9,10 c)6,8 d)15,18 4)8+4+2x5=? a)30 b)50 c)18 d)20 5)1001-11 of 13=? a) 7 b)1183 c)847 d)6 6) Write the smallest prime number. Muito the smallest odd prime number,...

Math, 5 months ago

Find (-32) × (-20) please say the answer in equation form...

Math, 5 months ago

Find the coordinates of the point P,Q,R and S please answer me these question fast please please please please please please please...

History, 10 months ago

Who were the Naths ?Answer in short...

History, 10 months ago

Gandhiji spent some time everyday spinning ‘Khadi’ on the charkha . He encouraged the use of khadi . What was his reason for doing this ?

Biology, 10 months ago

What would happen if in a gene encoding a polypeptide of 50 aminoacids, 25th codon(UAU) is mutated to UAA a) the polypeptide of 24 aminoacids will be formed b) two polypeptides of 24 and 25 aminoacids will be formed c)a polypeptide of 49 aminoacids will be formed d) a polypeptide of 25 aminoacids will be formed...