Question

99. In the following figure, straight lines l, m and n are parallel to each other and G is the mid-point of CD. Find :
(i) BG, if AD = 12 cm
(ii) CF, if GE = 4.6 cm
(iii) AB, if BC = 4.8 cm
(iv) ED, if FD = 8.8 cm

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Answer 1

Given that,

The straight line l, m and n are parallel to each other

G is the mid-point of CD

To find : BG

In △ACD

G is the mid-point of CD and BG ∥ AD as m ∥ n

⇒BG= 1/2 AD [ Converse of midpoint theorem ]

⇒BG = 1/2×6 = 3cm

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Answer 2

Answer:

i) It is given that

AB = 6 cm, BC = 4.8 cm and CA = 5.6 cm

To find: The perimeter of trapezium FBCA

It is given that

F is the mid-point of AB

We know that

BF = ½ AB = ½ × 6 = 3 cm ……. (1)

It is given that

E is the mid-point of AC

We know that

CE = ½ AC = ½ × 5.6 = 2.8 cm ……. (2)

Here F and E are the mid-point of AB and CA

FE || BC

We know that

FE = ½ BC = ½ × 4.8 = 2.4 cm …… (3)

Here

Perimeter of trapezium FBCE = BF + BC + CE + EF

Now substituting the value from all the equations

= 3 + 4.8 + 2.8 + 2.4

= 13 cm

Therefore, the perimeter of trapezium FBCE is 13 cm.

(ii) D, E and F are the midpoints of sides BC, CA and AB of Δ ABC

Here EF || BC

EF = ½ BC = ½ × 4.8 = 2.4 cm

DE = ½ AB = ½ × 6 = 3 cm

FD = ½ AC = ½ × 5.6 = 2.8 cm We know that

Perimeter of Δ DEF = DE + EF + FD

Substituting the values

= 3 + 2.4 + 2.8

= 8.2 cm

(b) It is given that

D and E are the mid-point of sides AB and AC

BC = 5.6 cm and ∠B = 720

To find: (i) DE (ii) ∠ADE

We know that

In Δ ABC

D and E is the mid-point of the sides AB and AC

Using mid-point theorem

DE || BC

(i) DE = ½ BC = ½ × 5.6 = 2.8 cm

(ii) ∠ADE = ∠B are corresponding angles

It is given that

∠B = 720 and BC || DE

∠ADE = 720

(c) It is given that

D and E are the midpoints of AB and BC respectively

DF || BC and AF = 2.6 cm

To find: (i) BEF is a parallelogram

(ii) Calculate the value of AC

Proof:

(i) In Δ ABC

D is the midpoint of AB and DF || BC

F is the midpoint of AC ….. (1)

F and E are the midpoints of AC and BC

EF || AB ….. (2)

Here DF || BC

DF || BE ….. (3)

Using equation (2)

EF || AB

EF || DB ….. (4)

Using equation (3) and (4)

DBEF is a parallelogram

(ii) F is the midpoint of AC

So we get

AC = 2 × AF = 2 × 2.6 = 5.2 cm