99^n is such a number begin with 8, least value of n?
(a) 11
(b) 10
(c) 9
(d) n does not exist; 99^n is such a number begin with 8, least value of n?; (a) 11; (b) 10; (c) 9; (d) n does not exist
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Your answer is (D) this is because so as to end with 8, the number must have 2 as it's prime factor but here ,
99=3×3×11
missing the factor 2.
Hence there is no value of n where 99^n ends with 8.
Voldemort2364:
Hope this answer helps you
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