Question

99% of employees in a company are Managers. How many managers should be
removed so that the percentage of Managers in that company becomes 98%, if there
are 100 employees in the company initially?​

Answer 1

Given:-

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There are 100 employees

99℅of employees in a company are Managers.

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Let:-

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x amount of employees leave the conference to reduce the percentage of managers to 98%.

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Then the number of managers left is 99−x and also the total number of employees in company reduced to 100−x .

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According to question:-

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Equation becomes -

$\tt{ \frac{99 - x}{100 - x} = \frac{98}{100} }$

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Do Cross Multiplication

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$\small \tt{100(99 - x) = 98(100 - x)}$

$\small \tt{9900 - 100x = 9800 - 98x}$

$\small \tt{- 100x + 98x =9800 - 9900}$

$\small \tt{- 2x = - 100}$

$\tt{x = \frac{ - 100}{ - 2} }$

$\tt{x = \frac{ - \cancel100}{ - \cancel2} }$

$\small\tt \purple{x = 50}$

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So 50 Managers should be removed to make percent of Managers in company is 98℅

Answer 2

or

Of 100 employees 99 of them are managers. To bring the percent to 98 one manager must leave the room!

hope it's helpful