Question

99. The length and breadth of a rectangular sheet of paper are 60 cm and 30 cm, respectively. A square of side 5 cm is cut and removed from the four corners of the sheet. The rest of the paper is folded to form a cuboid (without the top face). Find the volume of the cuboid so formed (in cm³).


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Answer 1

Step-by-step explanation:

The length and breadth of a rectangular sheet of paper are 60 cm and 30 cm, respectively. A square of side 5 cm is cut and removed from the four corners of the sheet. The rest of the paper is folded to form a cuboid (without the top face). Find the volume of the cuboid so formed (in cm³).

Answer 2

Answer:

Given that,

The length and breadth of a rectangular sheet of paper are 60 cm and 30 cm, respectively.

A square of side 5 cm is cut and removed from the four corners of the sheet.

The rest of the paper is folded to form a cuboid.

So, it means

↝ Length of cuboid, l = 60 - 2 × 5 = 60 - 10 = 50 cm

↝ Breadth of Cuboid, b = 30 - 10 = 20 cm

↝ Height of cuboid, h = 5 cm

[ See the attachment ]

So, Volume of cuboid thus formed is

$\sf \: \rm :\longmapsto\:{ \tt{ \: Volume_{Cuboid} = \bold{ l \times b \times h \: }}:}$

So, on substituting the values of l, b and h, we get

$\sf \: \rm :\longmapsto\:Volume_{Cuboid} \bold{= 50 \times 20 \times 5:}$

$\sf\rm :\longmapsto\:Volume_{Cuboid} \bold{= 5000 \: {cm}^{3}:}$

Hence,

$\purple{\sf :\longmapsto\:\boxed{ \tt{ \: Volume_{Cuboid} = 5000 \: {cm}^{3} \: }}}:$