Question

998^3. by using identity-(a-b)^3=a^3-b^3-3ab(a-b) ​

Answer 1

Answer:

998³=(1000-2) ³

(1000-2)³=(1000) ³-2³-3*1000*2(1000-2)

=1000000000-8-5,988,000

=994,011,992

Answer 2

Step-by-step explanation:

(a-b)^3= a^3-b^3-3ab(a-b)

-(a-b)^3= -a^3+b^3+3ab(a-b)

let a be 2 and b be 1000

-(a-b)^3= -a^3+b^3+3ab(a-b)

-(2-1000)^3= -2^3+1000^3+(3(2)(1000))(2-1000)

-(-998)^3= -8+1000000000+(6000)(-998)

(998)^3= -8+1000000000-5,988,000

(998)^3=994,011,992

Hope it helps you.

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