(998)³,Evaluate it using suitable identites.
Answers
Answered by
41
Solution :
Q. (998)³ = (1000 - 2)³
Using identity: (a - b)³ = a³ - b³ - 3ab (a-b)
= (1000)³ - (2)³ - 3(1000) (2) (1000 - 2)
= 1000000000 - 8 - 6000(998)
= 1000000000 - 8 - 5988000
= 1000000000 - 5988008
= 994011992
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Answered by
22
Solution :
*******************************************
We know the algebraic identity :
( a - b )³ = a³ - 3a²b + 3ab² - b³
Or
( a - b )³ = a³ - b³ - 3ab( a - b )
********************************************
Now ,
( 998 )³
= ( 1000 - 2 )³
= (1000)³ - 2³ - 3×1000×2(1000-2)
= 1000000000-8-6000×998
= 1000000000 - 8 - 5988008
= 994011992
Therefore ,
998³ = 994011992
••••
*******************************************
We know the algebraic identity :
( a - b )³ = a³ - 3a²b + 3ab² - b³
Or
( a - b )³ = a³ - b³ - 3ab( a - b )
********************************************
Now ,
( 998 )³
= ( 1000 - 2 )³
= (1000)³ - 2³ - 3×1000×2(1000-2)
= 1000000000-8-6000×998
= 1000000000 - 8 - 5988008
= 994011992
Therefore ,
998³ = 994011992
••••
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