Question

(999)² using identify for square of a binomial​

Answer 1

Step-by-step explanation:

999^2

(1000 - 1)^2

Using identity, (a - b)^2 = a^2 + b^2 -2ab

(1000 - 1)^2

(1000)^2 + (1)^2 - 2(1000×1)

1000000 + 1 - 2000

1000001 - 2000

998001

Answer 2

Step-by-step explanation:

(999)²

(1000 - 1)²

Using Identity -

(a - b)² = a² + b² - 2ab

[a = 1000 , b = 1]

(1000)² + 1² - 2(1000)(1)

1000000 + 1 - 2000

1000001 - 2000

998001

Hope it helps