Math, asked by vikashmaurya0312, 10 months ago

999) ^3
=(1000-1) ^3
=(x-y) ^3 = x^3-y^3-3xy(x-y)
=(1000-1) ^3= 1000^3 -1^3-3000(1000-1)
=1, 000,000,000-1-3000(1000-1)
=999, 999,999-3, 000,000-3, 000
=996996999

Sir, it is correct or wrong?
Because according to NCERT its answer is
997002999
(Polynomial example 23(ii))

Answers

Answered by mriganka53

Answer:

yes 23

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Step-by-step explanation:

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Answered by devansh77777

Answer:

23 is ur answer bro

Step-by-step explanation:

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999) ^3=(1000-1) ^3=(x-y) ^3 = x^3-y^3-3xy(x-y) =(1000-1) ^3= 1000^3 -1^3-3000(1000-1)=1, 000,000,000-1-3000(1000-1) =999, 999,999-3, 000,000-3, 000=996996999Sir, it is correct or wrong? Because according to NCERT its answer is997002999 (Polynomial example 23(ii)) ​

Answers

999) ^3
=(1000-1) ^3
=(x-y) ^3 = x^3-y^3-3xy(x-y)
=(1000-1) ^3= 1000^3 -1^3-3000(1000-1)
=1, 000,000,000-1-3000(1000-1)
=999, 999,999-3, 000,000-3, 000
=996996999

Sir, it is correct or wrong?
Because according to NCERT its answer is
997002999
(Polynomial example 23(ii))