999×[66÷{63+(19-16)}] using BODMAS
Answers
Answered by
21
Hey mate!
Here's ur answer dear:)
_____________________
_____________________
Using BODMAS:
B- bracket[{()}]
O- Of
D - Division ÷
M- multiplication ×
A - addition+
S-subtraction -
Now,
▶999×[66÷{63+(19-16)}]
▶ 999× [66÷ { 63+3}]
▶999× [66÷66]
▶ 999×0
▶0
_______________________
_______________________
Hope it helps!
☺☺☺
Here's ur answer dear:)
_____________________
_____________________
Using BODMAS:
B- bracket[{()}]
O- Of
D - Division ÷
M- multiplication ×
A - addition+
S-subtraction -
Now,
▶999×[66÷{63+(19-16)}]
▶ 999× [66÷ { 63+3}]
▶999× [66÷66]
▶ 999×0
▶0
_______________________
_______________________
Hope it helps!
☺☺☺
abhirajsingh35:
Thanks
Answered by
4
Answer:
999 999 X 56 / 53 plus by 19 - 16 and solve it simpler 50
Similar questions