999, 730, 511, 344, 215, ____.
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Answered by
6
Hi there!
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Clearly the No.s are nearer to perfect cubes and following alternate pattern of 1 less than and 1 more than the perfect squares.
As we go from left to right in series, the perfect cubes start decreasing from 1000
999 = 1000 - 1 = 10³ - 1
730 = 729 + 1 = 9³ + 1
511 = 512 - 1 = 8³ - 1
344 = 343 + 1 = 7³ + 1
215 = 216 - 1 = 6³ - 1
•°• Next term = 5³ + 1 = 125 + 1 = 126
----------- (Or) -------------
To get 'i'th term :
'i' th term
= (11-i)³-1 ; if i is odd
= (11-i)³+1 ; if i is even
Required term = 6th
=> i = 6 --Even
•°• Required No. = (11-6)³ + 1 = 5³ + 1 = 125 + 1 = 126
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Clearly the No.s are nearer to perfect cubes and following alternate pattern of 1 less than and 1 more than the perfect squares.
As we go from left to right in series, the perfect cubes start decreasing from 1000
999 = 1000 - 1 = 10³ - 1
730 = 729 + 1 = 9³ + 1
511 = 512 - 1 = 8³ - 1
344 = 343 + 1 = 7³ + 1
215 = 216 - 1 = 6³ - 1
•°• Next term = 5³ + 1 = 125 + 1 = 126
----------- (Or) -------------
To get 'i'th term :
'i' th term
= (11-i)³-1 ; if i is odd
= (11-i)³+1 ; if i is even
Required term = 6th
=> i = 6 --Even
•°• Required No. = (11-6)³ + 1 = 5³ + 1 = 125 + 1 = 126
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Answered by
0
The answer is 126...
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