(999).(abc)= def132, determine the digits a, b,c,d,e,f.............. please x-plain in detail.. decimal between 999 and abc (999.abc)
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999*abc=def132
we know 999*abc can be written as abc(1000-1)
abc*1000-1*abc
abc000-abc a b c 0 0 0
- a b c
__________________________
a b (c-1) (9-a) (9-b) (10-c)
___________________________
this no. ab(c-1)(9-a)(9-b)(10-c) = def132 (given)
on comparing we get,
10-c=2 => c=8
9-b=3 => b=6
9-a=1 => a=8
f=c-1 => f=7
e=b => e=6
d=a => d= 8
This can be verified by putting these values in the given equation
999*abc 999*868= 867132
def132= 867132
we know 999*abc can be written as abc(1000-1)
abc*1000-1*abc
abc000-abc a b c 0 0 0
- a b c
__________________________
a b (c-1) (9-a) (9-b) (10-c)
___________________________
this no. ab(c-1)(9-a)(9-b)(10-c) = def132 (given)
on comparing we get,
10-c=2 => c=8
9-b=3 => b=6
9-a=1 => a=8
f=c-1 => f=7
e=b => e=6
d=a => d= 8
This can be verified by putting these values in the given equation
999*abc 999*868= 867132
def132= 867132
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