Math, asked by arunayadupathi, 2 months ago

(999)cube
by using alegrabic identites

Answers

Answered by haziquehazique27oct2

0

Answer:

997002999

Step-by-step explanation:

999×999×999

=997002999

Answered by suhani5937

0

Answer:

(999)³ = (1000-1)³

(a-b)³=a³+b³+3ab(a-b)

(1000-1)³ = 1000³+1³+(3×1000×1)(3000-1)

= 1000000000+1+3000(3000-1)

= 1000000000+1+9003000-3000

=9000000+1

=1009000001

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