Question

9a
13. The factors of 27a3 +
27a?
+
4b
+
64b3
are:
16 b2
1
8h
1
1
45
a) (3a ++(3a + ) (3a +
b) (3a + ) (3a +
3a + b) (3a +
3a +
c) (3a + 4b)(3a + 4b)(3a + 4b)
d) 9a + ( )
1
1
9a +
8b
1
9a +
8b
8b
a​

Answer 1

Answer:

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