9a^2+4b^2+16c^2+12ab+16bc+24ca
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Answered by
2
Step-by-step explanation:
9a
2
+4b
2
+16c
2
+2ab−16bc−24ca
= (3a)
2
+(2b)
2
+(−4c)
2
+2(3a)(2b)+2(2b)(−4c)+2(−4c)(2a)
Suitable identities is (x+y+z)
3
=x
3
+y
3
+z
3
+2xy+2yz+2xz
Therefore, (3a)
2
+(2b)
2
+(−4c)
2
+2(3a)(2b)+2(2b)(−4c)+2(−4c)(2a)
= (3a+2b−4c)
2
I think this is the answer
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THIS IS THE RIGHT ANSWER
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