Math, asked by wwwanshikak643, 1 year ago

9a^2b^2x^2-16abcdx-25c^2d^2=0

Answers

Answered by Anonymous
60
 <marquee>☺☺Hi there☺☺</marquee>


9a2b2x2- 16abcdx - 25c2d2=0

here a= 9a2b2 , b= -16 abcd , c= -25c2d2

then D= (-16abcd) -4 * 9a2b2 *-25c2d2

= 256a2b2c2d2 + 900 a2b2c2d2

= 1156a2b2c2d2


hence it has real and unequal roots

x= -b +√D/2a

= -(-16abcd)+√1156a2b2c2d2/2 9a2b2

= 16abcd + 34abcd/18a2b2

= 50abcd/18a2b2

= 25cd/9ab


x= -b -√D/2a

= -(-16abcd) -√1156a2b2c2d2/2*9a2b2

= 16abcd- 34abcd/18a2b2

= -18abcd/18a2b2

= -cd/ab

Thanks♥♥
Answered by deathslayer90
7

Answer:

this is the ans :-) hope it'll help ya and sorry for uncleanliness :-D

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