Question

9a^4- 28a² +16 ÷ 3a - 2a -4

find the reminder by using remainder theorem ​

Answer 1

Answer:

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${\bold{\pink{ \underline{Using\:Remainder\:Theorem:-}}}}$

$p(x) = {9a}^{4} - {28a}^{2} + 16 \: \: and \: g(x) = 3a - 2a - 4$

$g(x) = 0$

$3a - 2a - 4 = 0$

$a - 4 = 0$

$a = 4$

$put \: x \: = 4 \: in \: p(x)$

$p(4) = 9{(4)}^{4} - 28 {(4)}^{2} + 16$

$= 9(256) - 28(16) + 16$

$= 2304 - 448 + 16$

$= 1856 + 16$

$= 1872$

$\small\red{\mid{\fbox{\tt{Hope it's helpful uh ♡♡}}\mid}}$