Math, asked by pranav4149, 3 months ago

9a^5-6a^2 by 3a^2 is​

Answers

Answered by Anonymous
13

9a⁵-6a²/3a²

=3a²(3a³-2)/3a²

=3a³-2

if (9a)⁵-(6a)²/(3a)²

=59049a⁵-36a²/9a²

=9a²(6561a³-4)/9a²

= 6561a³-4

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whether square is 'whole' or only for 'a'

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Answered by sumitsl
0

9a^5-6a^2 by 3a^2 is​ 3a^3 - 2

Step-by-step explanation:

Given:

  • Dividend: 9a^5-6a^2
  • Divisor: 3a^2

To be found: The result after dividing dividend by divisor.

Formula Used: Simplification of expressions using splitting the terms.

Solution:

We have our dividend  9a^5-6a^2 and divisor as 3a^2.

So, we have to divide our dividend by our divisor, so our expression will look like:

\frac{9a^5-6a^2}{3a^2}

Now we will split the terms and our expression will be:

\frac{9a^5}{3a^2}- \frac{6a^2}{3a^2}

Now we can easily divide our expression,

\frac{9a^5}{3a^2}- \frac{6a^2}{3a^2}\\ \\3a^3-2

So, 9a^5-6a^2 by 3a^2 is 3a^3-2.

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