Question

9a²-6a+1 factorize by splitting terms
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Answer 1

9a² - 6a + 1

9a² - 3a - 3a + 1

3a(3a -1) -1 (3a - 1)

(3a -1) (3a - 1)

Answer 2

Step-by-step explanation:

9a

9a 2

9a 2 −6a+1=0

9a 2 −6a+1=0=>9a

9a 2 −6a+1=0=>9a 2

9a 2 −6a+1=0=>9a 2 −3a−3a+1

9a 2 −6a+1=0=>9a 2 −3a−3a+1=>3a(3a−1)−1(3a−1)=0

9a 2 −6a+1=0=>9a 2 −3a−3a+1=>3a(3a−1)−1(3a−1)=0=>(3a−1)(3a−1)=0

9a 2 −6a+1=0=>9a 2 −3a−3a+1=>3a(3a−1)−1(3a−1)=0=>(3a−1)(3a−1)=03a=1

9a 2 −6a+1=0=>9a 2 −3a−3a+1=>3a(3a−1)−1(3a−1)=0=>(3a−1)(3a−1)=03a=1a=

9a 2 −6a+1=0=>9a 2 −3a−3a+1=>3a(3a−1)−1(3a−1)=0=>(3a−1)(3a−1)=03a=1a= 3

9a 2 −6a+1=0=>9a 2 −3a−3a+1=>3a(3a−1)−1(3a−1)=0=>(3a−1)(3a−1)=03a=1a= 31

9a 2 −6a+1=0=>9a 2 −3a−3a+1=>3a(3a−1)−1(3a−1)=0=>(3a−1)(3a−1)=03a=1a= 31

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