Question

9a²-6a-18 factorise this
please tell it fast​

Answer 1

Step-by-step explanation:

STEP :1

Equation at the end of step 1

(32a2 - 6a) - 18

STEP :2

STEP:3

Pulling out like terms

3.1 Pull out like factors :

9a2 - 6a - 18 = 3 • (3a2 - 2a - 6)

Trying to factor by splitting the middle term

3.2 Factoring 3a2 - 2a - 6

The first term is, 3a2 its coefficient is 3 .

The middle term is, -2a its coefficient is -2 .

The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 3 • -6 = -18

Step-2 : Find two factors of -18 whose sum equals the coefficient of the middle term, which is -2 .

-18 + 1 = -17

-9 + 2 = -7

-6 + 3 = -3

-3 + 6 = 3

-2 + 9 = 7

-1 + 18 = 17

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

3 • (3a2 - 2a - 6)