Question

(9b² – 3c²) + (2b²+ bc - 2c)-(2b²– -2bc-c²)-(c²+ 2bc – b²) = ​

Answer 1

Step-by-step explanation:

=9b^2-3c^2+2b^2+bc-2c-2b^2+2bc+c^2-c^2-2bc+b^2

=9b^2+2b^2-2b^2+b^2-3c^2+c^2-c^2+bc+2bc-2bc-2c

=10b^2-3c^2+bc-2c