9cos²x+4sin²x=5 then tanx=
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nihasetty:
i only got that answer
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change sin sqr x plus cos sqr x to 1
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9cos²x+4sin²x=5
4cos²x+ 4sin²x + 5cos²x = 5
4( cos²+ sin²x) + 5cos²x = 5
4 + 5cos²x = 5
cos² x = 1/5
cos x =1/√5
so,
H = √5. B=1. P = 2 (by Pythagoras theo)
so,
tanx= P / B = 2
4cos²x+ 4sin²x + 5cos²x = 5
4( cos²+ sin²x) + 5cos²x = 5
4 + 5cos²x = 5
cos² x = 1/5
cos x =1/√5
so,
H = √5. B=1. P = 2 (by Pythagoras theo)
so,
tanx= P / B = 2
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