Question

9f tan(A+B-C) = 1
Sec (B+C - A) = 2
find A, B, C = ?​

Answer 1

Answer:

The value of A is 60, B is 52.5 and C is

67.5.

Given,

tan(A + B- C) = 1

tan(A + B- C) = tan45°

A + B - C = 45 -(1),

Also, given,

sec(B+C - A) = 2

sec(B+C - A) = sec60°

B +C - A = 60 -(2),

Equation (1) + Equation (2),

2B 105 B= 52.5

Now, triangle ABC is a triangle,