9g of organic compound having CxHyOz required 9.6g of O2 for it's complete combustion and gave 13.2g of CO2, what is the empirical formula?
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Answer:%C=7.34g C12.04g compound×100%=61.0%%H=1.85g H12.04g compound×100%=15.4%%N=2.85g N12.04g compound×100%=23.7%
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