Math, asked by paripahuja, 2 days ago

9ky – 4hx +12hy – 3kx​

Answers

Answered by Anonymous
0

3ky -4hx + 12hy -kx

-4hx-kx+12hy+3ky

-x(4h+k)+3y(4h+k) (taking out common)

(-x+3y) (4h+k)

Answered by neha5390
2

Answer:

(3y – x) (3k + 4h)

Step-by-step explanation:

9ky – 4hx +12hy – 3kx

9ky – 3kx + 12hy – 4hx

3k(3y – x) + 4h(3y – x)

(3y – x) (3k + 4h)

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