Question

9p ² + 6p -4=0 solve by formula method​

Answer 1

$9 {p}^{2} + 6p - 4 = 0 \\ applying \: quadratic \: formula \: \\ p = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a } \\ here \: a = 9 \: b = - 5 \: c = - 4 \\ p = \frac{5 + - \sqrt{25 - 4( - 4)(9)} }{2 \times 9} \\ p = \frac{5 + - \sqrt{169} }{18} \\ p = 1 \: or \: \frac{ - 4}{9}$