Question

9p² - 36p² factorise using 3 identities​

Answer 1

(3p)^ - (6p)^

= (3p+6p)(3p-6p)

Answer 2

Given expression:

$9p^{2}-36p^{2}$.

Here, numbers $9$ and $36$ are perfect squares.

$9$ and $36$ are the square values of $3$ and $6$ respectively.

So, we can write the given expression as:

$(3p)^{2} -(6p)^{2}$

Here, above expression is in the form of $a^{2} -b^{2}$.

So, we can factorize by using the third identity, $[a^{2} -b^{2} =(a+b)(a-b)]$:

Here, $a=3p$ and $b=6p$.

$\implies(3p)^{2} -(6p)^{2} =(3p+6p)(3p-6p)$.

Hence, $(3p+6p)(3p-6p)$ is the factor of $9p^{2}-36p^{2}$.