Math, asked by gulpriya, 9 months ago

9sec2 theta -5cos2 theta=5+4sec2 theta

Answers

Answered by hari2980

0

Answer:

lhs

9sec²thita-5cos²thita

=9.1/cos²thita-5cos²thita

=9-5/cos²thita

=4/cos²thita

=4.sec²thita

your question's Rhs is in correct

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