Math, asked by samarth5549, 3 months ago

9secA×secA-9tanA×tanA=

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Answered by sharanamma447

2

Answer:

9secA×secA-9tanA×tanA

=9 sec square A-9tan square A

=9(sec^2-tan^2A)

=9(1)

=9

Answered by ISHWARI082421

3

Answer:

PLEASE MARK FOR BRAINLIEST

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