Question

9th
A body dropped from the top of a tower clears 9th/25 of the total height of the tower in its last second of flight.
The height of the tower is (g = 9.8m/s²)​

Answer 1

Answer:

H=125m

Explanation:

H=1/2gt^2

Time =(t-1)

using newton's second law of motion,

s=ut+1/2ut^2

since Hight is 9/25 of H or =9/25H

and H=s

therefore,

16/25H=0-1/2g(t-1)^2

16/25(1/2gt^2)=-1/2g(t-1)^2

16/25t^2=(t-1)^2

solving it gives u

t=5 secs

H=1/2gt^2

H=1/2*10*(5*5)

H=125m

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