Question

9th algebra x+3y =16 2x-y=4cross multiplication​

Answer 1

Your answer in iage above ⬆

$x = \frac{ - 27}{7} \: and \: y = \frac{ - 22}{7}$

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Answer 2

x = 4 and y = 4

it is given that,

x + 3y = 16 ......(1)

2x - y = 4 ...........(2)

we have to use cross multiplication method ( or Cramer's rule )

first write given equations in the standard form i.e., ax + by + c = 0

x + 3y + (-16) = 0....(1)

2x + (-1)y + (-4) = 0 .....(2)

now applying rule,

x/{3 ×( -4) - (-16) × (-1)} = -y/{1 × (-4) - (-16) × 2} = 1/{1 × (-1) - 3 × 2 }

⇒x/(-12 - 16) = -y/(-4 + 32) = 1/(-1 - 6)

⇒x/-28 = -y/28 = 1/-7

so, x = -28/-7 = 4

y = -28/-7 = 4

hence, value of x = 4 and y = 4

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