9th class solution of ex 10.5 q 2
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Step-by-step explanation:
let's suppose the centre of a circle is /o
Therom 10.8 angle subtended by the arc at the centre is double the angle subtended by the same Arc at any any point of circle
OA equal to AB given
aob is equlateralto Triangle
AOB equal to 60
AOB is equal to ACB
60/2 equal to ACB
ACB is 30
reflex angle is 360-AOB
360-60
300
300/2
AOB is 150
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