Math, asked by deepassraj, 4 months ago

9th Grade solution please

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Answers

Answered by vaibhavtiwari934
0

Answer:

D is a right answer ddddd

Answered by mathdude500
1

\large\underline{\sf{Given- }}

\rm :\longmapsto\: {5}^{x - 1} =  {25}^{x + 1}

\large\underline{\sf{To\:Find - }}

The value of x

\large\underline{\sf{Solution-}}

Given that

\rm :\longmapsto\: {5}^{x - 1} =  {25}^{x + 1}

We know, that

\boxed{ \rm{  {x}^{m + n}  =  {x}^{m}  \times  {x}^{n}}}

and

\boxed{ \rm{  {x}^{m  -  n}  =  {x}^{m}  \div   {x}^{n}}}

So, using this identity, the given expression reduced to

\red{\rm :\longmapsto\: {5}^{x} \div  {5}^{1} =  {25}^{x} \times  {25}^{1}}

\red{\rm :\longmapsto\: {5}^{x} \div  {5}^{1} =  {(5 \times 5)}^{x} \times  {5 \times 5}^{}}

\rm :\longmapsto\: \dfrac{ {5}^{x} }{5}  =  {5}^{2x} \times  {5}^{2}

\rm :\longmapsto\: {5}^{x}  =  {5}^{2x} \times  {5}^{2}  \times 5

We know that,

\boxed{ \rm{  {x}^{m + n}  =  {x}^{m}  \times  {x}^{n}}}

So, using this we get

\rm :\longmapsto\: {5}^{x} =  {5}^{2x + 2 + 1}

\rm :\longmapsto\: {5}^{x} =  {5}^{2x + 3}

We know,

\boxed{ \rm{  {x}^{m} =  {x}^{n}  \:  \implies \: m \:  =  \: n}}

So, we get

\rm :\longmapsto\:x = 2x + 3

\rm :\longmapsto\:x - 2x  =  3

\rm :\longmapsto\:- x  =  3

\bf\implies \:x =  -  \: 3

  • So, Option A) is correct.

Verification :-

Given expression is

\rm :\longmapsto\: {5}^{x - 1} =  {25}^{x + 1}

On substituting x = - 3, we get

\rm :\longmapsto\: {5}^{ - 3 - 1} =  {25}^{ - 3 + 1}

\rm :\longmapsto\: {5}^{ - 4} =  {25}^{ - 2}

\rm :\longmapsto\: {5}^{ - 4} =  {(5 \times 5)}^{ - 2}

\rm :\longmapsto\: {5}^{ - 4} =  {5}^{ - 2 \times 2}

\rm :\longmapsto\: {5}^{ - 4} =  {5}^{ -4}

Hence, Verified

Alternative Method :-

Given expression is

\rm :\longmapsto\: {5}^{x - 1} =  {25}^{x + 1}

can be rewritten as

\rm :\longmapsto\: {5}^{x - 1} =  {(5 \times 5)}^{x + 1}

\rm :\longmapsto\: {5}^{x - 1} =  {5}^{2(x + 1)}

\rm :\longmapsto\: {5}^{x - 1} =  {5}^{2x + 2}

We know,

\boxed{ \rm{  {x}^{m} =  {x}^{n}  \:  \implies \: m \:  =  \: n}}

So, using this, we get

\rm :\longmapsto\:x - 1 = 2x + 2

\rm :\longmapsto\:x - 2x = 1 + 2

\rm :\longmapsto\:- x = 3

\rm :\longmapsto\:x = -  \:  3

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