9th one please. 7th grade
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let the digit in ten's place be X.
then the digit at unit's place is 3x.
now the two digit number= X × 10+ 3x
= 13x
the number when the digits are reversed= 3x ×10 +X = 31x
then, According to the question,
13x + 36=31x
→31x-13x= 36
→18x =36
→ X= 36/18= 2
therefore the number= 10× x + 3× x
=10×2+3×2
=26 or if the reversed number is the original one it can also be 62.. :)
hope this helps
then the digit at unit's place is 3x.
now the two digit number= X × 10+ 3x
= 13x
the number when the digits are reversed= 3x ×10 +X = 31x
then, According to the question,
13x + 36=31x
→31x-13x= 36
→18x =36
→ X= 36/18= 2
therefore the number= 10× x + 3× x
=10×2+3×2
=26 or if the reversed number is the original one it can also be 62.. :)
hope this helps
Answered by
1
Answer:
Step-by-step explanation:
Original number=10x+3x
On interchanging
New number =30x+x
Therefore according to the question
10x+3x+36=31x
18x=36
x=2
Original number =26
New number =62
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let the digit in ten's place be X.
then the digit at unit's place is 3x.
now the two digit number= X × 10+ 3x
= 13x
the number when the digits are reversed= 3x ×10 +X = 31x
then, According to the question,
13x + 36=31x
→31x-13x= 36
→18x =36
→ X= 36/18= 2
therefore the number= 10× x + 3× x
=10×2+3×2
=26 or if the reversed number is the original one it can also be 62.. :)
hope this helps
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