9th one plzz need to solve help me out
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Hi! what is ur question plzzzzzz
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Is the diagram of the quadrilateral.
In right angled triangle,
By Pythagoras theorem
(BD)2 = (AB)2 + (AD)2
BD = (18)2 + (24)2
BD = 30
Area of triangle DBC = 1/2*b*h
= 1/2*40*30
= 600 m/square
Area of triangle ABD = 1/2*b*h
= 1/2*18*24
= 216 m/square
Area of quadrilateral ABCD = Area of triangle ABD + Area of triangle DBC
= 216+600
= 816 m/square
In right angled triangle,
By Pythagoras theorem
(BD)2 = (AB)2 + (AD)2
BD = (18)2 + (24)2
BD = 30
Area of triangle DBC = 1/2*b*h
= 1/2*40*30
= 600 m/square
Area of triangle ABD = 1/2*b*h
= 1/2*18*24
= 216 m/square
Area of quadrilateral ABCD = Area of triangle ABD + Area of triangle DBC
= 216+600
= 816 m/square
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Its sum I'll send afterwards
wtf
what will u send me???
Mind your language first
I'm sending it within few minutes
I'm sending it within few minutes
(BD)2 doesn't means that it should be multiplied with 2
but it should be multiplied 2 times (BD*BD)
but it should be multiplied 2 times (BD*BD)
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