Math, asked by siddharthnigamfan, 1 year ago

9th question and 10th question ( a) please answer

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Answered by anveshasingh191
1
Sol 10 )

1) 5x² + 16x + 3
= 5x² + 15x + x + 3
= 5x ( x + 3 ) + 1 ( x + 3 )
=> ( x + 3 )( 5x + 1 )

2) 3x² - 10x + 8
= 3x² - 6x - 4x + 8
= 3x( x - 2 ) - 4( x - 2 )
= ( x - 2 )( 3x - 4 )

3) 24x² - 41x + 12
= 24x² - 32x - 9x + 12
= 8x ( 3x - 4 ) - 3 ( 3x - 4 )
= ( 3x - 4 )( 8x - 3 )

4) x² + 21x + 104
= x² + 13x + 8x + 104
= x( x + 13 ) + 8( x + 13 )
= ( x + 13 )( x + 8 )

5) 24x² - 65x + 21
= 24x² - 56x - 9x + 21
= 8x( 3x - 7 ) - 3( 3x - 7 )
= ( 3x - 7 )( 8x + 3 )

6) 14x² + 19x - 3
= 14x² + 21x - 2x - 3
= 7x( 2x + 3 ) - 1( 2x + 3 )
= ( 2x + 3 )( 7x - 1 )

7) 6x² - 16x - 21
I think so this question is wrong....kindly check the question...

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Answered by Anonymous
1

Answer:

Sol 10 )

1) 5x² + 16x + 3

= 5x² + 15x + x + 3

= 5x ( x + 3 ) + 1 ( x + 3 )

=> ( x + 3 )( 5x + 1 )

2) 3x² - 10x + 8

= 3x² - 6x - 4x + 8

= 3x( x - 2 ) - 4( x - 2 )

= ( x - 2 )( 3x - 4 )

3) 24x² - 41x + 12

= 24x² - 32x - 9x + 12

= 8x ( 3x - 4 ) - 3 ( 3x - 4 )

= ( 3x - 4 )( 8x - 3 )

4) x² + 21x + 104

= x² + 13x + 8x + 104

= x( x + 13 ) + 8( x + 13 )

= ( x + 13 )( x + 8 )

5) 24x² - 65x + 21

= 24x² - 56x - 9x + 21

= 8x( 3x - 7 ) - 3( 3x - 7 )

= ( 3x - 7 )( 8x + 3 )

6) 14x² + 19x - 3

= 14x² + 21x - 2x - 3

= 7x( 2x + 3 ) - 1( 2x + 3 )

= ( 2x + 3 )( 7x - 1 )

Step-by-step explanation:

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