9th question pls answer anyone
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Consecutive Multiplies of 11= 11x, 11(x+1), 11(x+2)
If 2,3,5 are multiplies to the above numbers respectively=11x(2), 11(x+1)(3), 11(x+2)(5)
Sum of the no’s=22x+33(x+1)+55(x+2)=814
=22x+33x+55x+33+110=814
=110x+143=814
=110x=814-143=671
x=671/110=61/10=6.1
Required no’s=67.1, 78.1, 89.1
Check:
67.1x2+78.1x3+89.1x5
134.2+234.3+445.5=814
If 2,3,5 are multiplies to the above numbers respectively=11x(2), 11(x+1)(3), 11(x+2)(5)
Sum of the no’s=22x+33(x+1)+55(x+2)=814
=22x+33x+55x+33+110=814
=110x+143=814
=110x=814-143=671
x=671/110=61/10=6.1
Required no’s=67.1, 78.1, 89.1
Check:
67.1x2+78.1x3+89.1x5
134.2+234.3+445.5=814
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