Question

9th term of an ap is zero then show that its 29th term is double of its 19th term

Answer 1

Answer:

Step-by-step explanation:

9th term of an A.P is 0

Thus, a+(n-1)d, where n=9 will be 0

Where, a=First term of the A.P

            n=Number of terms

            d=Common difference

a+(9-1)d=0

Thus,a+8d=0

The 19th term will be a+18d= a+8d+10d= 0+10d= 10d

The 29th term will be a+28d= a+8d+20d=0+20d=20d

Hence 20d is double of 10d

Thus, the 29th term is double the 19th term for this particular A.P.