Question

9x^ - 16 = 0 by factorisation of method​

Answer 1

Step-by-step explanation:

9x²-16=0

a²-b²=(a+b)(a-b)

(3x+4)(3x-4)=0

If product of two number is zero, then either of the number is zero.

Therefore,

3x+4=0 OR 3x-4=0

3x=-4 OR 3x=4

x=-4/3 OR x=4/3