Question

9x^2+18x+2=0
solve by completing the square.​

Answer 1

Answer:

Please thank if it helps you

Answer 2

Answer:

the quadratic:

9 X square + 18 x plus 8

is in the form:

as square +bx +c

with a=9,b= 18 and c = 8

this has discriminant ∆ given by the formula:

∆=b square- 4 ac= 18 square - 4(9)(8) = 324-288=36=6 square

since this is positive and a perfect square, quadric will factor with integer coefficients.

we can find the same factorisation by completing the square:

note that 9 x square=(3x) square and 18 x = 2(3x)(3).

hence we find:

9 x square + 18 x + 8 = (3x) square+ 2 (3x)(3)+3 square -1

= (3x+3) square -1 square

= [(3x+3)-1] [(3x+3)+1]

= (3x+2)(3x+4)

thank you