9x^2-22x+8 factorise
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Answered by
2
9x^2-22x+8-----> multiply coefficient of highest degree and the constant.
i.e, 9*8=72
when we add 18 and 4,we get 22.
so it becomes 9x^2-(18+4)x+8
i.e,9x(x-2)-4(x-2)
so the factors are (x-2)(9x-4)
i.e, 9*8=72
when we add 18 and 4,we get 22.
so it becomes 9x^2-(18+4)x+8
i.e,9x(x-2)-4(x-2)
so the factors are (x-2)(9x-4)
Answered by
5
9x^2-22x+8
9x^2-18x-4x+8
9x(x-2)-4(x-2)
(9x-4)(x-2)
9x-4=0 x-2=0
9x=4 x=2
x=4/9
Therefore, x=4/9 or 2
9x^2-18x-4x+8
9x(x-2)-4(x-2)
(9x-4)(x-2)
9x-4=0 x-2=0
9x=4 x=2
x=4/9
Therefore, x=4/9 or 2
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