Question

வர்க்கமூலம் காண்க

9x^2-24xy+30x-40yz+25z^2+16y^2

Answer 1

$\huge\mathbb{SOLUTION}$

$\sf 9x^2-24xy+30xz-40yz+25z^2+16y^2$

$\sf =9x^2+16y^2+25z^2-24xy-40yz+30xz$

$\sf =(3x)^2+(-4y)^2+(5)^2+2×3x×(-4y)$

$\sf +2×(-4y)×5z+2×3x×5z$

$\sf =(3x-4y+5z)^2$

$\sf =(3x-4y+5z)(3x-4y+5z)$

$\huge\underline\frak\red{Note}$

$\sf Use\;identity\;(a+b+c)^2$

$\sf a^2+b^2+c^2+2ab+2bc+2ac$

Answer 2

வர்க்கமூலம்:  

$\begin{aligned}&9 x^{2}-24 x y+30 x-40 y z+25 z^{2}+16 y^{2}\end{aligned}$

தீர்வு:

$\begin{aligned}&9 x^{2}-24 x y+30 x-40 y z+25 z^{2}+16 y^{2}\end{aligned}$

$\sqrt{(3 x)^{2}+(5 z)^{2}+(4 y)^{2}-2(3 x)}\\ {(4 y)+2(3 x)(5 z)-2(5 z)(4 y)}$  

= $\sqrt{(3 x-4 y+5 z)^{2}}$

வர்க்கமூலம்=  $|3 x-4 y+5 z|$