Question

9x^2 - 34x - 8 = 0 solve this by middle term splliting method..​

Answer 1

Given :

$\longrightarrow\sf {9x}^{2} - 34x - 8 = 0$

To Find :

• Zeroes of equation by splitting middle term

Solution :

$\sf\implies {9x}^{2} - 34x - 8= 0 \\ \\ \sf\implies{9x}^{2} - 36x + 2x - 8 = 0 \\ \\\sf\implies 9x(x - 4) + 2(x - 4) = 0 \\ \\\sf\implies( 9x + 2)(x - 4) = 0$

Case 1

$\sf\implies9x + 2 = 0 \\ \\ \sf\implies9x = - 2 \\ \\\large\implies\boxed{\boxed {\sf\blue { x = - \frac{2}{9}}}}$

Case 2

$\sf\implies x - 4 = 0 \\ \\\large\implies\boxed{\boxed {\sf\green{ x = 4}}}$

Answer 2

✯✯ QUESTION ✯✯

${9x}^{2}-34x-8=0$..Solve this by middle term splitting term..

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✰✰ ANSWER ✰✰

$\longrightarrow{{9x}^{2}-34x-8=0}$

$\longrightarrow{{9x}^{2}-(36x-2x)-8=0}$

$\longrightarrow{{9x}^{2}-36x+2x-8=0}$

$\longrightarrow{9x(x-4)+2(x-8)=0}$

$\longrightarrow{(9x+2)(x-4)}$

Now ,

$\longrightarrow{9x+2=0}\\ \\ \longrightarrow{9x=-2}\\ \\ \longrightarrow\tt\pink{x=\dfrac{-2}{9}}$

$\longrightarrow{x-4=0}\\ \\ \longrightarrow\tt\red{x=4}$