Math, asked by chdkala1980, 7 months ago

9x^2+ 49y^2 + 42 xy, when x = 3 and y=1 find the value​

Answers

Answered by jsanthoshjoshhh
1

Answer:

256

Step-by-step explanation:

=9(3)^2+49(1)^2+42(3)(1)

=81+49+126

=256

hope you understand

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Answered by hrishikesh16
1

Answer:

9*9+49*1+42*3*1=81+49+126=256

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