Question

9x^2+4y^2+z^2-12xy+4yz-6zx factor​

Answer 1

Answer:

${( - 3x + 2y + z)}^{2}$

Step-by-step explanation:

$9 {x}^{2} + 4 {y}^{2} + {z}^{2} - 12y + 4y - 6zx$

$= {( - 3x)}^{2} + {(2y)}^{2} + {(z)}^{2} + 2( - 3x)(2y) + 2(2y)(z) + 2(z)( - 3x)$

Comparing with identity,

${a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca = {(a + b + c)}^{2}$

We get,

$= {( - 3x + 2y + z)}^{2}$